{"id":105,"date":"2007-05-12T10:24:09","date_gmt":"2007-05-12T14:24:09","guid":{"rendered":"http:\/\/www.joshbrews.com\/?p=105"},"modified":"2007-05-12T11:29:57","modified_gmt":"2007-05-12T15:29:57","slug":"calculating-mashing-efficiency","status":"publish","type":"post","link":"https:\/\/www.joshbrews.com\/?p=105","title":{"rendered":"Calculating Mashing efficiency"},"content":{"rendered":"

I realized that when I posted about calculating extract yield, that I forgot to explain how I calculated brewhouse effieiency. I use the same formula<\/p>\n

S.G. = ((((DBCG – Mousture Content – 0.002) * Brewhouse Efficiency * 46.214) * 0.001) +1)<\/p><\/blockquote>\n

Except that I remove the variable for brewhouse efficiency. The forumla will then assume that the mashing efficiency is at 100%<\/p>\n

S.G. = ((((DBCG – MC – 0.002) * 46.214) * 0.001) +1)<\/p><\/blockquote>\n

This will give us the theoretical maximum ppg of 1 lb of grain in 1 gallon of water. For example, Maris Otter Pale Malt<\/a>.<\/p>\n

S.G. = ((((0.805 – 0.03 – 0.002) * 46.214) * 0.001) +1)
\nS.G. = 1.035723422 or 35.7ppg<\/p><\/blockquote>\n

In my bitter 2 recipe I mashed 3 lbs. of Maris Otter Pale Malt<\/a>, and 1 lb of Briess 10 L crystal malt<\/a> collecting a final 2.5 gallons of wort at a S.G of 1.043 .<\/p>\n

The theoretical maximum ppg of 10 L crystal malt<\/a> is<\/p>\n

S.G. = ((((0.75 – 0.07 – 0.002) * 46.214) * 0.001) +1)
\nS.G = 1.031333092 or 31.3 ppg<\/p><\/blockquote>\n

Now, using the formula from John Palmer’s How To Brew<\/a>, we calculate the maximum theoretical points for our brew using the following formula<\/p>\n

((ppg Malt1 x lbs Malt1) \/ gallons of wort) + ((ppg Malt2 x lbs Malt2) \/ gallons of wort) = Total Points<\/p>\n

((35.7 x 3)\/2.5) + ((31.3 x 1)\/2.5) = 55.36<\/p><\/blockquote>\n

This is our theoretical maximum number of points per gallon.<\/p>\n

In the wort for the Bitter 2 recipe the S.G was 1.043 or 43 ppg. If we divide our real ppg by the theoretical ppg this will yeild our percentage yeild.<\/p>\n

43\/55 x 100 = 77.75%<\/p><\/blockquote>\n","protected":false},"excerpt":{"rendered":"

I realized that when I posted about calculating extract yield, that I forgot to explain how I calculated brewhouse effieiency. I use the same formula S.G. = ((((DBCG – Mousture Content – 0.002) * Brewhouse Efficiency * 46.214) * 0.001) +1) Except that I remove the variable for brewhouse efficiency. The forumla will then assume […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[10],"tags":[],"class_list":["post-105","post","type-post","status-publish","format-standard","hentry","category-general-brewing"],"_links":{"self":[{"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=\/wp\/v2\/posts\/105","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=105"}],"version-history":[{"count":0,"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=\/wp\/v2\/posts\/105\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=105"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=105"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.joshbrews.com\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=105"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}